A constant torque of 24.5 N · m is applied to a grindstone whose moment of inertia is 0.130 kg · m2. Using energy principles, and neglecting friction, find the angular speed after the grindstone has made 16.9 revolutions. Hint: the angular equivalent of Wnet = FΔx = 1 2 mvf2 − 1 2 mvi2 is Wnet = τΔθ = 1 2 Iωf2 − 1 2 Iωi2. You should convince yourself that this last relationship is correct. (Assume the grindstone starts from rest.)