A particle is projected from a point A with velocity of 21m/s at an angle of 53.1° to the horizontal. One second later another particle is projected at a point 0.3 m below A with initial velocty 31.5m/s at an angle of 36.9° to the horizontal. A) prove that the particles collide b) find the time of collision c) find the distance of collision from the point of projection

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s

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