A strip of copper 130 µm thick and 4.40 mm wide is placed in a uniform magnetic field of magnitude B = 0.79 T, that is perpendicular to the strip. A current i = 26 A is then sent through the strip such that a Hall potential difference V appears across the width. Calculate V. (The number of charge carriers per unit volume for copper is 8.47 × 1028 electrons/m3.)

V = 1.1658 × V

Explanation:

given data

strip of copper thick = 130 µm

strip of copper wide = 4.40 mm

uniform magnetic field of magnitude B = 0.79 T

current i = 26 A

number of charge carriers per unit volume = 8.47 × electrons/m³

solution

we know that number density is express as

n = \frac{Bi}{Vle}      ...............1

B  is uniform magnetic field and i is current  and V is hall potential difference and l is thickness and e is electron charge 1.6 ×  C

so V will be as

V = \frac{iB}{nle}      .....................2

so put here value and we get V

V =

V = 1.1658 × V

c. 7/3

step-by-step explanation:

a rational number is like pi- it is a repeating decimal.

a. is -1.8

b. 2.236068

c. 2.3333333333333333333

d.   is 3

i hope that ! =)

the answer is 3.1 his answer is wrong mines is right