The half-life of phosphorus-32 is 14.26 days. Calculate its decay constant.

5.62 x 10^-7 sec-1

Explanation:

Converting days to seconds:

14.26 x 24x60x60= 1.27 x 10^6

Half life= 0.693 / Decay constant

so

Decay constant = 0.693/1.27x 10^6

= 5.62 x 10^-7

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s

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