Physics, 22.04.2020 02:49 wolfiewolffromsketch

Coulomb measured the deflection of sphere A when spheres A and B had equal charges and were a distance d apart. He then made the charge on B one-third the charge on A. How far apart would the two spheres then have had to be for A to have had the same deflection that it had before

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Answer from: angelinamadriga

The new separation is $\bf{(d/\sqrt{3})}$ .

Explanation:

The expression of the force between two spheres is given by

$F = k\dfrac{q_{A}q_{B}}{d^{2}}~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(1)$

where, $q_{A}$ is the charge on sphere A, $q_{B}$ is the charge on sphere B, is constant and i the separation between two spheres.

The new value of charge on sphere B is $q_{B}^{n} = \dfrac{q_{A}}{3}$ . Consider the new separation between the spheres be . Under the new configuration the force between the spheres is given by

$F = k \dfrac{q_{A}(q_{A}/3)}{d'^{2}}~~~~~~~~~~~~~~~~~~~~~~~~~~~(2)$

Equating equation (1) and equation (2), we have

$~~~~&& \dfrac{1}{d'^{2}} = \dfrac{1}{3d^{2}}\\&or,& d' = \dfrac{d}{\sqrt{3}}$

So, the new separation is $(d/\sqrt{3})$ .

Answer from: Quest

the answer is b

explanation:

Answer from: Quest

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Coulomb measured the deflection of sphere A when spheres A and B had equal charges and were a distan...