In a mass spectrometer, a singly ionized 24Mg ion has a mass equal to 3.983 10-26 kg and is accelerated through a 3.00-kV potential difference. It then enters a region where it is deflected by a magnetic field of 526 G. Find the radius of curvature of the ion's orbit. Note: There are 10,000 G in 1 T and 1,000 V in 1 kV.

The radius of curvature of the ion's orbit is 0.59 meters

Explanation:

Given that,

Mass of the 24 Mg ion,

Potential difference, V = 3 kV

Magnetic field, B = 526 G

Charge on single ionized ion,

The radius of the the path traveled  by the charge is circular. Its radius is given by :

v is speed of particle.

v can be calculated using conservation of energy as :

Radius,

So, the radius of curvature of the ion's orbit is 0.59 meters.

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what is the speed of a softball that travels 20m in 2secs

speed = 20/2 = 10 m/s