Un ascensor de masa 900 kg levanta 6 pasajeros 30 m en 1 minuto, cada pasajero tiene una masa de 65 kg. Calcular el trabajo realizado y la potencia desarrollada por el motor.

Work done=114, 777 J

Power= 1912.95 W

Explanation:

Work done is the product of force and distance moved, expressed as

W=Fd

But F=mg hence substititing back into the formula of work done

W=mgd

Where m is mass, g is acceleration due to gravity, d is distance

Since they are six people, the mass will be 65*6=390 kg

Taking g as 9.81 m/s² and d as 30 m

W=390*9.81*30=114,777 J

Power is defined as the rate of work done per unit time

P=W/t

Where W is work done, P is power and t is time.

Substituting t for 60 seconds and W with 114,777 J

P=114,777÷60=1,912.95 W

the current is 0.6

voltage ÷ resistance = current

so 12 ÷ 20 = 0.6