A car passes the Eiffel tower driving at a constant rate of 60 km per hour. A second car, traveling at a constant rate of 75 km per hour, passes the Eiffel tower a while later and then follows the first car. It catches the first car after traveling a distance of 75 km past the Eiffel tower. How many minutes after the first car passed the Eiffel tower did the second car pass the Eiffel tower

300 minutes.

Explanation:

Given,

Speed of car 1 = 60 Km/h

Speed of car 2 = 75 Km/h

distance travel by car 2 to catch car 1 = 75 Km

time taken to catch the car = ?

Relative velocity between the car = 75 - 60 = 15 Km/h

t = 5 hrs

t = 5 x 60 = 300 minutes.

answer; ///i believe that the correct answer is (45*) at a 45 degree check first good

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.