Physics, 21.04.2020 00:00 thnguyen0720

A turntable is off and is not spinning. A 0.8 g ant is on the disc and is 9 cm away from the center. The turntable is turned on and 0.8 s later it has an angular speed of 45 rpm. Assume the angular acceleration is constant and determine the following quantities for the ant 0.4 s after the turntable has been turned on. Express all quantities using appropriate mks units.

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Answer from: elijah207

Complete Question

The complete is shown on the first uploaded image

$\alpha = 5.89 rad/s^2$

$w__{0.4}}= 2.36 \ rad/s$

v= 0.212m/s

a_t= 0.5301 m/s

a_r = 0.499 m/s

a = 0.7279 m/s

$F_{net}=5.823*10^{-4}N$

Explanation:

From the question we are told that

mass of the ant is $m_a = 0.8g = \frac{0.8}{1000} = 0.00018kg$

The distance from the center is $d = 9cm = \frac{9}{100} = 0.09m$

The angular speed is $w = 45rpm = 45 * \frac{2 \pi }{60} = 1.5 \pi$

The time taken to attain angular acceleration of 45rpm t_1 = 0.8s

The time taken is t_2 = 0.4 s

The angular acceleration is mathematically represented as

$\alpha = \frac{w}{t}$

$= \frac{1.5}{0.8}$

$\alpha = 5.89 rad/s^2$

The angular velocity at time t= 0.4s is mathematically represented as

$w__{0.4s}} = \alpha * t_2$ Recall angular acceleration is constant

= 5.89 * 0.4

$w__{0.4}}= 2.36 \ rad/s$

The linear velocity is mathematically represented as

$v = w__{t_2}} * r$

= 2.36 * 0.09

v= 0.212m/s

The tangential acceleration is mathematically represented as

$a_{t} = \alpha * r$

= 5.89 * 0.09

a_t= 0.5301 m/s

The radial acceleration is mathematically represented as

$a_r = \frac{v^2}{r}$

$= \frac{0.212^2}{0.09}$

a_r = 0.499 m/s

The resultant velocity is mathematically represented as

$a = \sqrt{a_t^2 + a_r^2}$

$= \sqrt{0.53^2 + 0.499^2}$

a = 0.7279 m/s

The net force is mathematically represented as

$F_{net} = 0.0008 * 0.7279$

$F_{net}=5.823*10^{-4}N$

A turntable is off and is not spinning. A 0.8 g ant is on the disc and is 9 cm away from the center.

Answer from: Quest

elly's long hair:

a. if the salon only takes cash, then this isn't the problem. it doesn't matter how much she has in her checking account. she can't get a haircut until she has the cash.

b. if she has overdraft protection, then there's no problem. she can go ahead and write a check that her account can't cover, then sometime later, pay the bank some outrageous usury for loaning her a few bucks for a few days, but with beautiful hair.

c. if elly has some principles, and doesn't want to write a bad check, then now she has a problem. her desire for the new hairstyle is in conflict with her honesty and integrity.

d. if the bank will not process a check she writes, then even if she had a million $$ in her account, she couldn't use any of it. the amount she has in her account is not the problem. and if i may suggest, she might as well close her checking account, and put the money where it'll work for her. it's not doing her a bit of good in a checking account, since she can't write any checks.

justin can't pay the full balance:

a. he can't even handle the credit limit he has now. under no circumstances should he ask for a higher limit.

b. he can ask for the grace period to be extended. but that's no solution, the bank will almost certainly refuse anyway, and there are much better options. he knew the rules of his credit card when he started using it.

c. he definitely should pay the interest on the balance, plus as much of the balance as he can cover at the same time.

d. he definitely should pay the minimum otherwise they could shut down his card. he should also pay as much more as he possibly can. he should also remember the awkward situation he's in, stop buying stuff on credit that he can't afford, and avoid adding any more debt.

i'd say that justin's best best option isn't on this list of choices. what he has to do: pay as much as he can at least the minimum payment plus as much more as he can and then avoid adding more debt.

Answer from: Quest

it breaks and dirupture other materials and other sencews from the bottom

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A turntable is off and is not spinning. A 0.8 g ant is on the disc and is 9 cm away from the center....