Consider 500 g of silver (atomic mass 107 g/mol). Assume that the temperature is high enough that equipartition applies. We heat the silver by immersing it in water; by measuring the temperature change of the water we compute that 300 J of heat energy entered the silver.

What was the change in temperature of the silver?

A. 2.57 K
B. 0.6 K
C. 4.99 K
D. 169 K
E. 0.0466 K

A. 2.57 K

Explanation:

From specific heat capacity,

Q = cmΔT Equation 1

Where Q = Amount of heat that entered into silver, m = mass of silver, c = specific heat capacity of silver, ΔT = change in temperature of the silver.

make ΔT the subject of the equation

ΔT = Q/cm Equation 2

Given: Q = 300 J, m = 500 g = 0.5 kg

Constant: c = 233 J/kg.K

Substitute into equation 2

ΔT = 300/(0.5×233)

ΔT  = 300/116.5

ΔT = 2.57 K

Hence the right option is A. 2.57 K

well, you would divide 135 by 33 to get your answer. then that is how many seconds it would take. boardman should fly about 132 m or 4.090909090909091 seconds.

scattering of light by tiny particles in air to produce the colors we see on sky, is dependent on the following factors:

(i) wavelength of light

(ii) size of the scattering particle  

(iii) distance traveled by light through the atmosphere.

according to rayleigh's law of scattering, the amount of scattering is inversely proportional to the fourth power of its wavelength. shorter the wavelength, greater is its scattering. hence violet/blue light is scattered more than red.

sun's light is a composite light ( visible light) with wavelengths in the range 400 nm (violet) to 700 nm (red). as sunlight passes through our atmosphere, the molecules of air scatter light according to their wavelengths. during sunrise and sunset, the sun's position is below the horizon. hence light from the sun travels a greater distance in the atmosphere when compared to its position a noon.

as sunlight enters the earth's atmosphere, blue light is scattered away and at the end of its journey in the sky, only red and orange wavelengths remain in the beam.

hence at sunrise and sunset, the sky appears reddish orange.