What is the electric potential energy of a charge that experiences a force of 3.6 × 10–4 N when it is 9.8 × 10–5 m from the source of the electric field?

3.528×10⁻⁸ V.

Explanation:

Electric Potential: This can be defined as the work done in an electric field in moving a unit charge from infinity to any point. The S.I unit of electric potential is Volt (V) or J/C.

From the question,

V = Fd Equation 1

Where V = Electric Potential, F = force experienced by the charge, d = distance.

Given: F = 3.6×10⁻⁴ N, d = 9.8×10⁻⁵ m.

Substitute into equation 1

V = 3.6×10⁻⁴( 9.8×10⁻⁵)

V = 3.528×10⁻⁸ V.

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