A straight wire is carrying current along the x-axis in the x direction. A second straight wire is carrying an equal current along the y-axis in the y direction. Both of the wires are in the x-y plane, and all questions pertain only to the magnetic field at points in the x-y plane. Which of the following statements are true about the net magnetic field in the four quadrants of the x-y plane (designated by compass notation)?
True/False: Points with the field in the -x direction could belocated in the Northeast quadrant
True/False: Points with B = 0 could be located in the Southeastquadrant
True/False: The strongest into-the-page field occurs in theNorthwest quadrant
True/False: Points with B = 0 could be located in the Northeastquadrant
True/False: The strongest out-of-page field occurs in the Southwestquadrant

    m₁v₁ + m₂v₂ = (m₁ + m₂)vmomentum is conserved.the left-hand side of the equation represents the momentum in the system before the collision.the right-hand side represents the momentum in the system after the collisionm₁ and v₁ represents the mass and the velocity of the physics blockm₂ and v₂ represents the mass and velocity of the ball of puttyv represents the final velocity of the combined mass.the question states the two masses stick together. they combined mass has its own velocity with the body mass the sum of the two objects' massestheir combined momentum is (m₁ + m₂)vto find the magitude of (m₁ + m₂)v, we need to add the vectors on the left-hand side of the equation: m₁v₁ + m₂v₂.note the diagram. i have positioned the vectors in accordance with their directions.the magnitude of the resultant can be calculated using the pythagorean theorem since this is a right triangle situation (north and west are perpendicular)|(m₁ + m₂)v| =  √[ (m₁v₁)² + (m₂v₂)² ]|(m₁ + m₂)v| =  √[ (1.5kg·8.0m/s)² + (0.40kg·20m/s)² ]|(m₁ + m₂)v| =  14.4 kg m/sfor two significant figures (assuming that 20m/s is two), this rounds to 14 kg m/s