. At a sudden contraction in a pipe the diameter changes from D1 to D2. The pressure drop, Δp, which develops across the contraction is a function of D1 and D2, as well as the velocity, V, in the larger pipe, and the fluid density, rho, and viscosity, μ. Use D1, V, and μ as repeating variables to determine a suitable set of dimensionless parameters.

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14

answer; equivalent to a one(1) horsepower motor;

the only real purpose of sputnik 1 was to beat the us into space. we were getting close to launching a useful satellite, explorer 1 - which launched on january 31, 1958. the ussr had to beat that, so they launched sputnik 1 on october 4, 19