Newton's rings are visible when a planoconvex lens is placed on a flat glass surface. For a particular lens with an index of refraction of n= 1.50 and a glass plate with an index of n= 1.80, the diameter of the third bright ring is 0.700 mm .If water = (1.33) now fills the space between the lens and the glass plate, what is the new diameter of this ring? Assume the radius of curvature of the lens is much greater than the wavelength of the light

the new diameter of the third ring = 0.607 mm

Explanation:

Consider the radius of bright ring when air is in between the lens and the plate ;

Using the expression: for the radius of the   bright ring since the liquid (water ) of the refractive index 'n' is now in between the lens and the plate;

where;

= number of fringe

λ = wavelength

R = radius

n = refractive index of water

Now ;

the radius r of the third bright ring when the air is in between lens and plate =

The new radius of the third bright fringe is

Calculating the new diameter ; we have:

d(3) = 2(r(3))

d(3) = 2(0.3035)

d = 0.607 mm

Thus, the new diameter of the third ring = 0.607 mm

note: the given question is incomplete.

complete question is given below.

which is an example of kinetic energy?

a. the energy stored in ethanol  

b. a hockey puck sliding across the ice  

c. a compressed spring  

d. a ball sitting at the top of a ramp

solution: the kinetic energy is the energy posses by the virtue of the motion of the object.

in the given options, a, c and d are the example of potential energy because it is the energy posses by the virtue of the rest of the object. but option b has the kinetic energy as the object is in motion.

hence, a hockey puck sliding across the ice   is the apex example of kinetic energy.

so, the option (b) a hockey puck sliding across the ice   is the correct option.