Physics, 16.04.2020 00:54 michelle230
Consider simple harmonic oscillator with energy quantum =10-20 J. That is, the state energies are 0,,, etc. It is in an environment with temperature 320 K.
1) Over all the possible states in equilibrium, what is the most probable energy of the oscillator?
Answers: 2
![P (E = 0) = e^{-0} / [e^{-0} + e^{-\epsilon /K_BT_a} + e^{-2\epsilon /K_BT_a}]](/tpl/images/0603/9762/cbba6.png)
![= 1/[1 + e^{-2.26} + e^{-4.53}]](/tpl/images/0603/9762/30b8c.png)
![P (E = \epsilon ) = e^{-\epsilon /K_BT_a} / [e^{-0} + e^{-\epsilon/K_BT_a }+ e^{-2*\epsilon/K_BT_a}]](/tpl/images/0603/9762/6be42.png)
![= e^{-2.26}/[1 + e^{-2.26} + e^{-4.53}]= 0.104/1.11= 0.0936](/tpl/images/0603/9762/fbca9.png)
![P (E = 2*\epsilon ) = e^{-2\epsilon/K_BT_a }/ [e^{-0} + e^{-\epsilon/K_BT_a} + e^{-2\epsilon /K_BT_a}]](/tpl/images/0603/9762/5cea2.png)
![= e^{-4.53}/[1 + e^{-2.26} + e^{-4.53}]= 0.011/1.11= 0.009](/tpl/images/0603/9762/0e997.png)
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Consider simple harmonic oscillator with energy quantum =10-20 J. That is, the state energies are 0,...
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