A proton travels through uniform magnetic and electric fields. The magnetic field is in the negative x direction and has a magnitude of 2.35 mT. At one instant the velocity of the proton is in the positive y direction and has a magnitude of 2540 m/s. At that instant, what is the magnitude of the net force acting on the proton if the electric field is (a) in the positive z direction and has a magnitude of 4.19 V/m, (b) in the negative z direction and has a magnitude of 4.19 V/m, and (c) in the positive x direction and has a magnitude of 4.19 V/m?

a) 1.62*10^{-18}N

b) 2.84*10^{-19}N

c) 1.16*10^{-18}N

Explanation:

The net force is given by the expression:

By the right hand rule, we know that the direction of the magnetic force is

j X -i = k

Hence, the direction of the magnetic force is the +z direction.

(a) E=4.19V/m k

where we have used q=9.1*10^{-31}kg.

(b) E=-4.19V/m k

(c) E=4.19V/m i

In this case the net force will have two components:

and its magnitude will be:

hope this helps!!

the motion of a pendulum is a classic example of mechanical energy conservation. a pendulum consists of a mass (known as a bob ) attached by a string to a pivot point. as the pendulum moves it sweeps out a circular arc, moving back and forth in a periodic fashion.

the order for strong to weak forces such as

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force

the fundamental forces are those forces that act between to objects or element to make interactions. there are four types of fundamental forces such as strong and weak nuclear forces (due to protons and electrons), electromagnetic force (due to the motion of electrons) and gravitational force (due to orbital movement of the planet). if these forces are arranged on the basis of their maximum strength then the order is

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force