Light from a laser of wavelength λ1 shines normally on a pair of narrow slits separated by distance D. This results in a difference in angle between the central and first intensity maxima of 0.02 radians. A second laser of wavelength λ2=2λ1 then shines on the same slit system. The new angular difference between the central first intensity maxima is closest to:

Explanation:

The angular position of first intensity maxima is given by the expression

= λ / d where λ is wave length of light and d is slit separation

putting the values given in the problem. ,

.02 = λ₁ / D

Now wavelength has been increased to 2λ₁

angular separation of first maxima

=  2λ₁ /D

= 2 x .02

= .04 radians.

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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50 inches should be the resultant vector