An elevator is designed such that when traveling upward, it has a constant acceleration from rest to its cruising speed of 2.00 m/s in a time of 3.00 s. The elevator has a mass of 675 kg and you may ignore friction. What is the average power of the elevator motor during this period?

The average power of the elevator motor during this period is 450 W .

Explanation:

Given :

Initial velocity , u = 0 m/s .

Final velocity , v = 2 m/s .

Time taken , t = 3 s .

Mass of elevator , M = 675 kg .

We need to find the average power of the elevator motor during this period.

Now , we know power is given by :

Now , work done is given by :

W=F.d

Here , F is the force applied and d is the distance covered .

Now , acceleration is given by :

Also , displacement is :

Therefore , work done is :

SO , power P is :

Therefore , the average power of the elevator motor during this period is 450 W .

see earlier answer