The air in a 6.00 L tank has a pressure of 2.00 atm. What is the final pressure, in atmospheres, when the air is placed in tanks that have the following volumes if there is no change in temperature and amount of gas?
a. 1.00 L
b. 2500. mL
c. 750. mL
d. 8.00 L

Explanation:

Given that,

Initial volume of tank, V = 6 L

Initial pressure, P = 2 atm

We need to find the final pressure when the air is placed in tanks that have the following volumes if there is no change in temperature and amount of gas:

(a) V' = 1 L

It is a case of Boyle's law. It says that volume is inversely proportional to the pressure at constant temperature. So,

(b) V' = 2500 mL

New pressure becomes :

(c) V' = 750 mL

New pressure becomes :

(d) V' = 8 L

New pressure becomes :

Hence, this is the required solution.

f=ma a/f/m a= 480/60 a = 8m/s/s that is quick wow

as we know our atmosphere or air have different levels. every level has other gasses, and every gas has another permeability. when the light comes from lower permeability to higher permeability, it changes its direction. so that means that when the light comes from the moon to the earth, it changes it's direction many more times. it basically means that the shape of the light part of the moon is changed on the earth.

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