Two point charges, A and B, are separated by a distance of 19.0 cm . The magnitude of the charge on A is twice that of the charge on B. If each charge exerts a force of magnitude 46.0 N on the other, find the magnitudes of the charges

The charge on point A is = 2.4 × C

The charge on point B is = 1.2 × C

Explanation:

Given data

Distance (r) = 0.19 m

Magnitude of the charge on A is twice that of the charge on B  i.e.

F = 46 N

We know that force between the charges is given by

= 1.2 × C

= 2 ×

= 2 × 1.2 ×

= 2.4 × C

Therefore the charge on point A is = 2.4 × C

The charge on point B is = 1.2 × C

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