Determine the frequency of the 2nd harmonic of a spring that has a 3rd harmonic resonance of f3=512 Hz.

a.341 Hz

b.768 Hz

c.1536 Hz

d.512 Hz

1) 341 Hz

Explanation:

When a string vibrates, it can vibrate with different frequencies, corresponding to different modes of oscillations.

The fundamental frequency is the lowest possible frequency at which the string can vibrate: this occurs when the string oscillate in one segment only.

If the string oscillates in n segments, we say that it is the n-th mode of vibration, or n-th harmonic.

The frequency of the n-th harmonic is given by

where

n is the number of the harmonic

is the fundamental frequency

Here we have:

is the frequency of the 3rd harmonic

So the fundamental frequency is

And so, the frequency of the 2nd harmonic is:

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2

spare some change and give it to the poor

explanation:

plz : ((