You toss a 0.150-kg baseball straight upward so that it leaves your hand moving at 20.0 m/s. The ball reaches a maximum height y2. What is the speed of the ball when it is at a height of y2/2? Ignore air resistance.

14.14 m/s

Explanation:

mass of ball, m  0.150 kg

initial velocity, u = 20 m/s

g = 10 m/s²

The final velocity at the height is zero. Total height is y2.

Use third equation of motion,

v² = u² - 2 gh

0 = 20 x 20 - 2 x 10 x y2

y2 = 20 m

Let v is the velocity at height y2/2 .

v² = u² - 2 gh

v² = 20 x 20 - 2 x 10 x 10

v² = 400 - 200

v = 14.14 m/s

Thus, the velocity at half of the height is 14.14 m/s.

with the invention of the automobile, the woman of the house could drive to the store and get groceries. women were also free to socialize more. during world war ii women were allowed to work in factories to the war effort and could drive to work or ride mass transit buses to their jobs.

well, you would divide 135 by 33 to get your answer. then that is how many seconds it would take. boardman should fly about 132 m or 4.090909090909091 seconds.