The only force acting on a 2.0 kg canister that is moving in an xy plane has a magnitude of 6.0 N. The canister initially has a velocity of 2.2 m/s in the positive x direction, and some time later has a velocity of 7.9 m/s in the positive y direction. How much work is done on the canister by the 6.0 N force during this time

W_net = 57.57J

Explanation:

We are given;

Mass of canister; m = 2kg

Initial velocity of the canister; v_i = 2.2 m/s

Final velocity of the canister; v_f = 7.9 m/s

From work energy theorem, the net work done is equal to the change in kinetic energy. Thus;

W_net = ΔKE

W_net = KE_f - KE_i

W_net = (1/2)mv_f² - (1/2)mv_i²

W_net = (1/2)m(v_f² - v_f²)

Plugging in the relevant values to give;

W_net = (1/2)(2)(7.9² - 2.2²)

W_net = 57.57J

a solenoid is created by wrapping a l = 90 m long wire around a hollow tube of diameter d = 4.5 cm.   the wire diameter is d = 0.9 mm.   the solenoid wire is then connected to a power supply so that a current of i = 9 a flows through the wire.

randomized variablesl = 90 m

d = 4.5 cm

d = 0.9 mm

i = 9 a                                          

write an expression for the number of turns, n, in the solenoid. you do not need to take into account the diameter of the wire in this calculation.

calculate the number of turns, n, in the solenoid.

write an expression for the length of the solenoid (l2) in terms of the diameter of the hollow tube d.

calculate the length of the solenoid (l2)   in meters.

calculate the magnitude of the magnetic field at the center of the solenoid in teslas.

explanation: