Suponiendo que se mide la longitud de una cuadra de 100 m de longitud con un error de 40 cm; luego se mide la altura de un poste de señalización de 2 m con un error de 4 mm ¿en cuál de las medidas se obtiene mayor exactitud? Determinar el error relativo y el error porcentual

The pole measure has greater accuracy

Explanation:

For the case of the block measure:

absolute error: 40 cm = 0.4 m

actual measure: 100 m

Relative error = absolute error/actual measure =  0.4/100 = 0.004

percentage error = Relative error * 100 = 0.004*100 = 0.4 %

For the case of the pole measure:

absolute error: 4 mm = 0.004 m

actual measure: 2 m

Relative error = absolute error/actual measure =  0.004/2 = 0.002

percentage error = Relative error * 100 = 0.002*100 = 0.2 %

Greater accuracy correspond to the lower error

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day

t = 1/400 h   ⇔ 0.0025 h ⇔ 9s ⇔ 0.15 m

any of the answers are correct.