A rectangular metal bar has length of 20cm, width of 5cm. Mass of the block is 2kg and its density is 5000kg/m3. Find the height of the metal bar.

0.04m

Explanation:

Mass of the block (m) = 2kg

density (p) = 5000kg/m3

Volume (v) = ?

Recall that density is obtained by dividing mass by volume. i.e density = mass / volume

p = m / v

Make v the subject formula

v = m / p

So, v = 2kg / 5000kg/m3

v = 0.0004 m3

Now given that the volume of the rectangular metal bar is 0.0004m3, find its height:

length of metal bar (l) = 20cm

convert length in centimeters to meters

(If 100cm = 1m

20cm = 20/100 = 0.2m)

width of bar (w) = 5cm

convert width in centimeters to meters

(If 100cm = 1m

5cm = 5/100 = 0.05m)

height (h) = ?

Volume of metal bar = l x w x h

0.0004 m3 = 0.2m x 0.05m x h

0.0004 m3 = 0.2m x 0.05m x h

0.0004 m3 = 0.01m² x h

h = 0.0004 m3 / 0.01m²

h = 0.04m

Thus, the height of the rectangular metal bar is 0.04 meters

i don't know that i agree with that but what's the question ?

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day