Three resistors with values of 4.0Ω, 6.0Ω, and 8.0Ω, respectively, are connected in series. What is their equivalent resistance?
a.) 18Ω
b.) 8.0Ω
c.) 6.0Ω
d.) 1.8 Ω

Option a) 18Ω

Explanation:

Given that,

R1 = 4.0Ω

R2 = 6.0Ω

R3 = 8.0Ω

Since the three resistors are connected in series, the equivalent resistance (Rtotal) of the circuit is the sum of each resistance.

i.e Rtotal = R1 + R2 + R3

Rtotal = 4.0Ω + 6.0Ω + 8.0Ω

Rtotal = 18Ω

Thus, the equivalent resistance is 18Ω

answer///isobars;