An ac current is given by i= 495 sin( 9.53 t, with i in milliamperes and t in milliseconds.

The frequency of the AC current is 1.51 Hz.

Explanation:

An AC current is given by :

......(1)

The general equation of AC current is given by :

.....(2)

Comparing equation (1) and (2) we get :

We know that,

So, the frequency of the AC current is 1.51 Hz.

The frequency in Hz of the AC current given by I = 495sin(9.43t) is; f = 1500.83 Hz

The current is given by;

I = 495sin(9.43t)

Now, comparing this equation to the general expression of AC Current which is;

I = A sin ωt

It means that;

A = 495

ω = 9.43 rad/ms

Now we want to find the frequency which is in Hz. Hz is simply cycles/s. Thus, let us convert ω from rad/ms to rad/s to get;

1 rad/ms = 1000 rad/s

Thus: 9.43 rad/ms = 9.43 × 1000/1

ω = 9430 rad/s

Now, we know that formula for angular velocity is;

ω = 2πf

Thus;

f = ω/2π

Plugging in the relevant values;

f = 9430/(2π)

f = 1500.83 Hz

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The complete question is;

An AC current is given by I = 495sin(9.43t), with I in milliamperes and t in milliseconds. Find the frequency in Hz.