One billiard ball is shot east at 2.0 m/s. a second, identical billiard ball is shot west at 0.8 m/s. the balls have a glancing collision, not a head-on collision, deflecting the second ball by 90° and sending it north at 1.55 m/s. what are the speed and direction of the first ball after the collision?

speed = 1.96 m/s

direction = 52.25° south of east

Explanation:

given that:

the velocity of the first ball

the velocity of the second ball

the final velocity of the second ball

The mass of the identical balls

However from law of conservation of momentum

along X- axis

=  ( 2.0 - 0.8 ) m/s

= 1.2 m/s

along Y-axis

then the final speed of the first ball

and direction

 south of east.  

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answer: 2×10^-2kg

explanation: density= mass per volume

vol=mass/density

converting to s.i units we have;

3÷1000kg = 0.003

1.5÷100m = 0.15

0.003/0.15 = 0.02kg