A youngs interference experiment is performed with blu-green argon laser light .The slits is 0.5mm, and the screen is located 3,30m from the slits .the first bright fringe is located 3.40mm from the center of the interference pattern. what is the wavelength of the argon laser light?

515 nm

Explanation:

The equation that gives the position of the maxima (bright fringes) in the interference pattern produced on a distant screen by the diffraction of light through two slits is

where

y is the distance of the maximum (bright fringe) from the central maximum

m is the order of the maximum

is the wavelength of the light used

D is the distance of the screen

d is the separation between the slits

In this problem we have:

is the separation between the slits

D = 3.30 m is the distance of the screen

m = 1 (we are analyzing the 1st bright fringe)

is the distance of the 1st bright fringe from the central maximum

Solving for , we find the wavelength of the light used:

answer: strength i guess

explanation:

a solenoid is created by wrapping a l = 90 m long wire around a hollow tube of diameter d = 4.5 cm.   the wire diameter is d = 0.9 mm.   the solenoid wire is then connected to a power supply so that a current of i = 9 a flows through the wire.

randomized variablesl = 90 m

d = 4.5 cm

d = 0.9 mm

i = 9 a                                          

write an expression for the number of turns, n, in the solenoid. you do not need to take into account the diameter of the wire in this calculation.

calculate the number of turns, n, in the solenoid.

write an expression for the length of the solenoid (l2) in terms of the diameter of the hollow tube d.

calculate the length of the solenoid (l2)   in meters.

calculate the magnitude of the magnetic field at the center of the solenoid in teslas.

explanation: