A box with a mass of 0.6-kg falls from a very tall building. While free-falling it is subjected to a frictional drag force given by Fdrag = bv2, where v is the speed of the object and b=5.5 N•s2/m2 What is the terminal speed that the box will reach?

the terminal speed that the box will reach v = 1.0355 m/s

Explanation:

The drag force is the resultant force component that acts in the relative motion direction of the body.

Here we have Fdrag = bv²

But Fdrag = mg

Therefore F = 0.6 × 9.81 =5.886 N

v² = Fdrag / b = 5.886 N/(5.5 N s²/m²)

v = 1.0355 m/s

gravititional force is a force that is acting around you, it is non-contactable and it is a force that pulls you to the core of the earth.

brainliest

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂