Suppose you want to determine the resistance of a resistor that is nominally 100 . You should be able to apply 10 V across the resistor and measure about 100 mA. Since there are variations in your resistor values, the resistor you chose is not exactly 100 . First, you measure y1 = 102 mA. Then, you ask a friend to measure, and she gets y2 = 97 mA. a. What do you get for the resistance value if you use the two measurements separately (two values)? b. Set it up as a linear system with measurement y = [y1y2]T and a single resistance value x.
Answers: 1
![y = \left[\begin{array}{ccc}y_{1} &y_{2} \end{array}\right] ^{T}](/tpl/images/0587/7598/7be28.png)
![y = \left[\begin{array}{ccc}y_{1} \\y_{2} \end{array}\right]](/tpl/images/0587/7598/50b42.png)
![y = \left[\begin{array}{ccc}102*10^{-3} \\97*10^{-3} \end{array}\right]](/tpl/images/0587/7598/66d37.png)
![x = \left[\begin{array}{ccc}100\end{array}\right]](/tpl/images/0587/7598/cad81.png)
![\left[\begin{array}{ccc}102*10^{-3} \\97*10^{-3} \end{array}\right] = \left[\begin{array}{ccc}G_{1} \\G_{2} \end{array}\right] \left[\begin{array}{ccc}100\end{array}\right]\\\left[\begin{array}{ccc}G_{1} \\G_{2} \end{array}\right] = \left[\begin{array}{ccc}102*10^{-5} \\97*10^{-5} \end{array}\right]](/tpl/images/0587/7598/9ffc8.png)
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