The block moves up an incline with constant speed. What is the total work Wtotal done on the block by all forces as the block moves a distance L = 4.00 m up the incline? Include only the work done after the block has started moving at constant speed, not the work needed to start the block moving from rest.

zero

Explanation:

Since the work on the block is the sum of the works done by every force acting on the block:

Wtotal = Wk + Wn + Wg

Wk ; work done by the friction force, Fk

Wn: work done by the normal force, Fn

Wg: work done by the gravity force, Fg

Since, by definition of work:

Wk = Fk*L*cos(180°) = - Fk*L

Wn = Fn*L*cos(90°) ) = 0

Wg = Fg*L*cos(90-∅) = Fg*L*sin(∅)

Wtotal = - Fk*L + 0 + Fg*L*sin(∅) (1)

Since the block moves to constant velocity, by 2° Newton's law: the sum of all forces are zero.

Using diagram of all forces, is posible demostrate:

Fk = Fg*sin(∅)

Reeplacing in the (1) expression:

Wtotal = 0

answer: the direction of the wind is expressed as the direction from which the wind is blowing. for example, easterly winds blow from east to west, while westerly winds blow from west to east.

explanation:

a cold ice-tea.

pour in room temperature or cold water. cover the pitcher and refrigerate. steep white or green tea for 6 to 8 hours; steep black or oolong tea for 8 to 12 hours.jun 28, 2015