A 0.5 kg ball is dropped vertically onto a floor, hitting with a speed of 20 m/s. It rebounds with a speed of 15 m/s immediately after the collision. (a) What is the impulse in N-s acting on the ball during the contact

2.499Ns

Explanation:

Impulse is defined as change I'm momentum of a body. It is expressed as;

According to Newton's second law;

F = ma

F = m(v-u)/t

Ft = m(v-u) = Impulse

Impulse = Ft

Impulse = m(v-u)

F is the force acting on the ball

t is the time taken

m is the mass of the body

v is the final velocity

u is the initial velocity

To get impulse, we need to get time t first using the equation of motion v = u+gt

20 = 15+(9.8)t

20-15 = 9.8t

5 = 9.8t

t = 5/9.8

t = 0.51secs

Since Impulse = Ft

F = mg = 0.5(9.8)

F = 4.9N

Impulse = 4.9×0.51

Impulse acting on the ball during contact = 2.499Ns

the independent variable, the one that is intentionally manipulated, is whether or not the car hits the barrier.

the dependent variable, the one that you measure the response in, is the distance that the washers travel.

answer: decibel

explanation: