A biker accelerates from Om/s to 8m/s ub 3 seconds. What is his acceleration? Is
this acceleration higher than that of a car wihich accelerates from 0 to 30m/s in
8 seconds

The acceleration of the biker is 2.67m/s² while that of the car is 3.75m/s². So, the acceleration of the biker is NOT HIGHER than that of the car.

Explanation:

Given that,

acceleration of biker A= ?

Initial velocity of biker Vi = Om/s

Final velocity of biker Vf = 8m/s

Time taken (t) = 3 seconds

Since acceleration is the rate of change of velocity per unit time

i.e Acceleration = (Vf - Vi) / t

A = (8m/s - 0m/s) / 3s

A = 2.67 m/s²

To know which is higher, calculate the acceleration of the car

acceleration of car A= ?

Initial velocity of car Vi = Om/s

Final velocity of car Vf = 30m/s

Time taken (t) = 8 seconds

Acceleration = (30m/s - 0m/s) / 8s

A = 30m/s / 8s

A = 3.75 m/s²

Since, the acceleration of the biker is 2.67m/s² while that of the car is 3.75m/s², the acceleration of the biker is NOT HIGHER than that of the car.

a and b sometimes have a positive value