An object of unknown mass is initially at rest and dropped from a height h. It reaches the ground with a velocity v1 . The same object is then raised again to the same height h but this time is thrown downward with velocity v1 . It now reaches the ground with a new velocity v2 . How is v2 related to v1 ?

Explanation:

The velocity v₁ can be calculated with the kinematic formula:

Since the object is initially at rest, v₁ becomes:

Where g is the acceleration due to gravity. Now, the velocity v₂ can be calculated with the same formula, but now the initial velocity is v₁:

Substituting v₁ in this expression and solving for v₂, we get:

Now, dividing v₂ over v₁, we get the expression:

It means that v₂ is √2 times v₁.

depends on what you mean by "group." for order, it would be coleoptera (beetles). for class, it would be insecta (insects). for phylum, it would be the arthropoda (animals with jointed exoskeletons).

explanation: