G Consider two blocks of masses m1 and m2 at the top of two frictionless inclines, respectively. Both blocks start to slide down from rest at the same height. However, the incline on which m1 sits is at an angle of 20° with the horizontal, while the incline on which m2 sits is at 45°. Which block will be going faster at the bottom of its incline?

Explanation:

acceleration of an object on an inclined plane due to gravitational pull

= g sinθ . This acceleration is irrespective of mass of the object coming down . It only depends on the inclination .

If θ is larger , sinθ will be larger hence gravitational acceleration on inclined surface will be greater . It happens so because a component of weight mg is acting on the body . This component is mgsinθ . The other component mgcosθ acts perpendicular to surface hence it does not contribute to its acceleration .

acceleration produced  = force / mass

= mgsinθ / m

= gsinθ .

in the given case , the inclination of plane with mass m₁ is less , hence its downward acceleration will be lesser as compared with the acceleration of m₂ which is put on a surface with  greater inclination .

f=ma newton's second law 7x8=56n

you'd use the equation that establishes a relationship between  energy  and  wavelength, which looks like this

e=h⋅cλ, where

λ  - the wavelength of the photon; c  - the speed of light, usually given as  3⋅108m/s; h  -  planck's constant, equal to  6.626⋅10−34j s

plug the value you were given for the energy of the photon in the above equation to get the wavelength

e=h⋅cλ⇒λ=h⋅ce

λ=6.626⋅10−34js⋅3⋅108ms−1.257⋅10−24j=1.581⋅10−1m