You illuminate a slit with a width of 70.3 μm with a light of wavelength 719 nm and observe the resulting diffraction pattern on a screen that is situated 2.11 m from the slit. What is the width, in centimeters, of the pattern?

4.3 cm

Explanation:

We are given that

Width,d=70.3

Wavelength,

We have to find the width in cm of the pattern.

The angle for the first minimum m=1

The width of the pattern=

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14