Two in-phase loudspeakers that emit sound with the same frequency are placed along a wall and are separated by a distance of 5.00 m. A person is standing 12.0 m away from the wall, equidistant from the loudspeakers. When the person moves 50 cm parallel to the wall, she experiences destructive interference for the first time.

What is the frequency of the sound?

Frequency = 42Hz

Explanation: first destructive will be:

(1 + 0.5)× V/ lamda = F

Please find the attached file for the solution

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