Una avioneta para aplicar agroquímicos debe alcanzar una velocidad de 28 m/s para poder despegar. Si el motor provee una aceleración efectiva de despegue de 1.5 m/s2, determine:

La longitud efectiva mínima que debe tener la pista para que la avioneta pueda despegar, si en la carrera de despegue recorre la pista partiendo del reposo, desde un extremo de la misma.
El tiempo que le toma despegar bajo las condiciones del inciso anterior.
porfaaa!

135 peaches were sold.

Because the dept in the ocean

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.

Make them both to where they have the denominator of 18that makes 3/2 equal 27/18 and 1/9 equal 2/18so now you have  27/18x+5=2/18subtract 5 from the other sideso now you have 27/18x+2/18-5then subtract 2/18 from 27/18 to get 25/18x=-5then divide 25/18 by -5 and your answer will be  -5/18