Steam enters a horizontal pipe operating at steady state with a specific enthalpy of 3000 kJ/kg and a mass flow rate of 0.5 kg/s. At the exit, the specific enthalpy is 1700 kJ/kg. If there is no significant change in kinetic energy from inlet to exit, the rate of heat transfer between the pipe and its surroundings is:

-650 KW

Explanation:

We are given that

Initial specific enthalpy=

Exit specific enthalpy=

Mass flow rate,

We have to find the rate of  heat transfer between the pipe and its surroundings.

Change in specific enthalpy=

Heat transfer rate=

Heat transfer rate=

Heat transfer rate=-650 KW

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explanation:

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