A 140 g mass is connected to a light spring of force constant 5 N/m that is free to oscillate on a horizontal, frictionless track. The mass is displaced 3 cm from the equilibrium point and released from rest.

(A) Find the period of its motion.
(B) Determine the maximum speed of the block.
(C) What is the maximum acceleration of the block?
(D) Express the position, velocity, and acceleration as functions of time in SI units.

Explanation:

mass attached m = .14 kg

force constant k = 5N / m

displacement

= amplitude of oscillation

A = .03 m

A ) period of motion =

= 2 x 3.14

T = 1.05 s

B ) maximum speed of block = angular velocity x amplitude

= (2π /T)  x A

= (2 x 3.14 x .03) / 1.05

= .1794 m / s

17.94 cm /s

C )

maximum acceleration = angular velocity² x amplitude

= (2π /T)² x A

= (2π /1.05)² x .03

= 1.073 m / s²

D )

position

S = A cos ωt , ω is angular velocity

S = .03 cos(2πt /T)

= .03 cos 5.98 t

v =ω A sin(2πt /T)

= 5.98 x .03 sin5.98t

= .1794 sin5.98t

acceleration = ω²A sin5.98t

= 1.073 sin5.98t

the answer is ampere

the ampere is used to measure electricity. an ampere is a unit of electric current equal. a unit of measure for the flow of current in a circuit. one ampere is the amount of current flow provided when one volt of electrical pressure is applied against one ohm of resistance.