Jasmine walks from the back of room 822 to the front. The room has a length of
20 meters.
a. What is the distance Jasmine walked?
b. What is the displacement of Jasmine from start to finish?
C. Now Jasmine walks half way back. What is her new total distance walked?
d. What is her new total displacement?

a. Distance walked by Jasmine is 20 m.

b. DIsplacement of Jasmine is 20 m.

c. Total distance walked by Jasmine is 30m.

d. New displacement of Jamsine is 10m.

Explanation:

The given problem concerns the problem of distance and displacement.

Given data- The length of the room is 20 m in which Jasmine walks from back to front.

a.Distance covered during the journey- Since she has walked from the    back to front, she had covered the length of the room i.e. 20 m. Hence, she has walked 20m.

b.Displacement of Jasmine from start to finish- She has walked from the starting to last point. Hence the displacement would equal her distance i.e. 20m

c.Now she walks half way back- hence total distance would be 1.5 times length of the room (since she walked half the length of the room)- 1.5*20= 30m

d.Total new displacement- Since she is now half way across the length of the room, her new displacement would be 20-10m= 10m

54 degrees incident angle = reflected angle

angle is from normal turned to line of ray

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