A football player weighing 110 kg and traveling at +6 m/s runs head on into another player who weighs 150 kg and is traveling at -4 m/s. In which direction will they travel after they collide (stuck together) and what would their combined velocity be?

This is an inelastic collision. The equation for an inelastic collision is:

(110)(6) + (150)(-4) = (110 + 150)(vf)

660 - 600 = 260vf

60 = 260vf

vf = 0.2308 m/s

They will travel in the positive direction, right, and their combined velocity will be 0.2308 m/s.

Hope this helps!! :)

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards