Figure 3
(b) The surface is tilted to an angle of 37 degrees from the horizontal, as shown above in Figure 3 The blocks are each given a push so that at the instant show
Other
they are
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1. Each block has a mass of 0.20 kg Calculate the magnitude of the net force exerted on the two block system at the instant shown above

  3.92 N (straight down)

  2.36 N (down, parallel to the plane)

Explanation:

The only force acting on the system is apparently that due to gravity. The mass of the system is the sum of the masses of the blocks, so is ...

  0.20 kg + 0.20 kg = 0.40 kg

The force due to gravity is given by ...

  F = ma = (0.40 kg)(9.8 m/s²) = 3.92 N . . . (straight down)

That force is acting straight down, so is at an angle with respect to the direction the blocks are constrained to move.

The force down the plane is (3.92 N)·sin(37°) ≈ 2.359 N . . . (down the plane)

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Comment on the answer

We have given two answers to the question, because in this frictionless system, the force acting normal to the plane of motion is irrelevant to the system dynamics. The question asked for the net force on the system, which is the force due to gravity, so we have given that magnitude also.

answer: the exterior temperature of commercial jet planes as they leave the stratosphere and return to the ground increases steadily.

explanation:

the lower most layer of atmosphere is troposphere which extends from 0 to 12 km above the surface of the earth. the temperature initially decreases as distance is increased from the earth's surface. commercial jets fly in lower part of the stratosphere. the stratosphere extends upto 50 km. the temperature in stratosphere starts rising again due to presence of ozone which traps the uv rays.

thus, when the planes leave the stratosphere and return to the ground, the exterior temperature increases steadily.