A 63.0 \mu F capacitor is connected to a generator operating at a low frequency. The rms voltage of the generator is 4.00 V and is constant. A fuse in series with the capacitor has negligible resistance and will burn out when the rms current reaches 15.0 A. As the generator frequency is increased, at what frequency will the fuse burn out

Explanation:

AC Circuit

When connected to an AC circuit, the capacitor acts as an impedance of module

Where w is the angular frequency of the power source and C is the capacitance.

If the capacitor is the only element connected to a circuit, then the Ohm's law establishes that

Where V and I are the rms voltage and current respectively. Replacing the value of Z, we have

Solving for w

The question provides us the following values

Plugging in the values

Since

Then

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