Abaseball pitcher throws a fastball horizontally at a speed of 43.0 m/s. ignoring air resistance, how far does the ball drop between the pitcher’s mound and home plate, 60 ft 6 in away? . express your answer using si units.

The distance covered by the ball between the pitcher’s mound and home plate is 0.864 meters.

Explanation:

Given that,

Horizontal velocity of the football, v = 43 m/s

In this case, we need o find the distance covered by the ball between the pitcher’s mound and home plate, 60 ft 6 in away. It implies,

Let t is the time taken by the football to cover that much distance. So,

Initial velocity of the ball in vertical direction is equal to 0. So, the distance covered by the ball between the pitcher’s mound and home plate is given by :

So, the distance covered by the ball between the pitcher’s mound and home plate is 0.864 meters. Hence, this is the required solution.

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find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2