Amountain climber jumps a 1.9-m-wide crevasse by leaping horizontally with a speed of 9.0 m/s.. if the climber's direction of motion on landing is −45°, what is the height difference between the two sides of the crevasse?

y = 4.13 m

Explanation:

Since the climber jumps horizontally with speed 9 m/s

so the time taken by the climber to cross the distance is given as

now we know that he land with a velocity at an angle of 45 degree

so we will have

so we can find the vertical displacement by using kinematics

the average speed is 24.57 km/hr

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