1. The Hertzsprung - Russell Diagram shows the relationship between a star's absolute
and surface
2. Brightness increases as you go higher or lower on the diagram?_
3. In which direction, does temperature increase on the graph?
4. What colors are represented by the Spectral Class letters: 0 =
,A=
B =
,K=
,M=
,,Z=
5. What is the color of the hottest star?
What is the color of the coolest star?
6. Type of stars: W =
V =
7. What well known star is represented by the star labeled Y?
8. What type of star is Y?
What is temperature & color of star Y?
9. Which type of star is the letter U?
What is its color?
10. What is the temperature of star T?
What is its brightness?
11. Which star is brighter T or U?
Which star has cooler temperatures, T or U?
12. Which star is brighter X or Z?
Which star is hotter X or Z?
13. Which star is smaller X or Z?
Which star is larger V or X?
14. Does temperature increase or decrease in the Main - Sequence stars as they get brighter?
15. Why is the Sun brighter than the White Dwarfs even though the White Dwarfs are hotter? THIS QUESTION IS WORTH 45 points

From negative to negative

    m₁v₁ + m₂v₂ = (m₁ + m₂)vmomentum is conserved.the left-hand side of the equation represents the momentum in the system before the collision.the right-hand side represents the momentum in the system after the collisionm₁ and v₁ represents the mass and the velocity of the physics blockm₂ and v₂ represents the mass and velocity of the ball of puttyv represents the final velocity of the combined mass.the question states the two masses stick together. they combined mass has its own velocity with the body mass the sum of the two objects' massestheir combined momentum is (m₁ + m₂)vto find the magitude of (m₁ + m₂)v, we need to add the vectors on the left-hand side of the equation: m₁v₁ + m₂v₂.note the diagram. i have positioned the vectors in accordance with their directions.the magnitude of the resultant can be calculated using the pythagorean theorem since this is a right triangle situation (north and west are perpendicular)|(m₁ + m₂)v| =  √[ (m₁v₁)² + (m₂v₂)² ]|(m₁ + m₂)v| =  √[ (1.5kg·8.0m/s)² + (0.40kg·20m/s)² ]|(m₁ + m₂)v| =  14.4 kg m/sfor two significant figures (assuming that 20m/s is two), this rounds to 14 kg m/s