It takes a target 0.015 seconds to stop a bullet. What is the mass of a bullet traveling 320m/s if the target uses a force of 81 newtons to stop it.

I don't know i want points can I be brainliest if i answer?

Explanation:

n order to be able to determine the force that accelerates the bullet, you first need to determine the bullet's acceleration.

You know what the length of the gun barrel and what the bullet's exit velocity are, which means that you can write

v

2

exit

=

v

2

0



=0

+

2

⋅

a

⋅

l

Solve the above equation for

a

to get

a

=

v

2

exit

2

⋅

l

a

=

800

2

m

2

s

2

2

⋅

0.75

m



=75 cm

=

426,666.7 m/s

2

This means that the force that's accelerating the bullet is equal to

F

=

m

⋅

a

F

=

0.015 kg



=15 g

⋅

426

,

666.7

m

s

2

=

6400

kg

⋅

m

s

2



=Newton

=

6400 N

Answer link

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j