As a football player moves in a straight line [displacement (3.00 mm)i^i^ - (6.50 mm)j^j^], an opponent exerts a constant force (126 NN)i^i^ (168 NN)j^j^ on him. How much work does the opponent do on the football player

The amount of work done by the opponent on the football player is expressed as

Work is said to be done if a force applied to an object causes the object to move over a distance.

Given the following parameters

displacement =

Force =

Work done = Force * distance

Substitute the given parameters into the formula:

Hence the amount of work done by the opponent on the football player is expressed as

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Work done,

Explanation:

Displacement,

Force,

Work done by the opponent do on the football player is given by :

So, the work done by the opponent do on the football player is  .

work: w = fd (given)

work done by chet   =50*1 = 50 j

work done by mika =40*2 = 80 j

work done by sara =30*1.5 = 45 j

work done by bill =60*0.5 = 30 j

students in order from the greatest amount of work done to the least is mika> chet> sara> bill

hence option (b) is correct.

this is poiselle's equation from fluid mechanic in physics. mech eng